No.
01 - Binary Search Tree and Double-linked List

Convert a binary search tree to a sorted double-linked list. We can only change the target of pointers, but cannot create any new nodes.

No. 04 - Paths with Specified Sum in Binary Tree

All nodes along children pointers from root to leaf nodes form a path in a binary tree. Given a binary tree and a number, please print out all of paths where the sum of all nodes value is same as the given number.

No. 06 - Post-order Traversal Sequences of Binary Search Trees

Determine whether an input array is a post-order traversal sequence of a binary tree or not. If it is, return true; otherwise return false. Assume all numbers in an input array are unique.

No. 31 - Binary Search Tree Verification

How to verify whether a binary tree is a binary search tree?

No. 45 - Closest Node in a Binary Search Tree

Given a binary search tree and a value

Convert a binary search tree to a sorted double-linked list. We can only change the target of pointers, but cannot create any new nodes.

No. 04 - Paths with Specified Sum in Binary Tree

All nodes along children pointers from root to leaf nodes form a path in a binary tree. Given a binary tree and a number, please print out all of paths where the sum of all nodes value is same as the given number.

No. 06 - Post-order Traversal Sequences of Binary Search Trees

Determine whether an input array is a post-order traversal sequence of a binary tree or not. If it is, return true; otherwise return false. Assume all numbers in an input array are unique.

No. 31 - Binary Search Tree Verification

How to verify whether a binary tree is a binary search tree?

No. 45 - Closest Node in a Binary Search Tree

Given a binary search tree and a value

*k*, please find a node in the binary search tree whose value is closest to*k*.
Given a binary search tree, please check whether there are two nodes in it whose sum equals a given value.

helpful..Thanks:)

ReplyDeleteTks very much for your post.

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Ni Hau,

DeleteYour blog is such a complete read. I like your approach with Binary Tree Interview Questions. Clearly, you wrote it to make learning a cake walk for me.

I want to make a dynamic array of char* returned by a function. I need to save the name of files contained inside a folder to a dynamic array of char*.

My IDE is dev-c++, my favorite, my language is C.

If the data is expensive to compare, the number of comparisons used even by a binary search might be too many. So instead of looking at the data themselves, you’ll condense (hash) the data to an integer (its hash value) and keep all the data with the same hash value in the same place. This task is carried out by using the hash value as an index into an array.

Awesome! Thanks for putting this all in one place. Very useful!

Thanks a heaps,

Micheal

which traversal is same in a binary tree and its mirror image

ReplyDeletePostorder traversal

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DeleteThis grouping of your BT problems is ridiculously helpful

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ReplyDeleteTks very much for your post.

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public BSTNode toDoublyLinkedlIst() {

ReplyDeleteBSTNodetest = inorder2(root);

while (test != null ) {

System.out.println(test.data);

test = test.left;

}

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public BSTNode inorder2(BSTNode node) {

if (node.left == null && node.right == null) {

return node;

}

BSTNode nodeLeft = inorder2(node.left);

nodeLeft.right = node;

BSTNode nodeRight = inorder2(node.right);

nodeRight.left = node;

return nodeRight;

}

public BSTNode toDoublyLinkedlIst() {

ReplyDeleteBSTNodetest = inorder2(root);

while (test != null ) {

System.out.println(test.data);

test = test.left;

}

return null;

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public BSTNode inorder2(BSTNode node) {

if (node.left == null && node.right == null) {

return node;

}

BSTNode nodeLeft = inorder2(node.left);

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BSTNode nodeRight = inorder2(node.right);

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}

Tks very much for your post.

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Source: Download Ebook: Ultimate Guide To Job Interview Questions Answers:

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